Complete question is;
At an outdoor market, a bunch of bananas is set on a spring scale to measure the weight. The spring of force constant 16.0 N/m sets the full bunch of bananas into vertical oscillatory motion, which is harmonic with an amplitude 0.15 m. The maximum speed of the bananas is observed to be 2.34 m/s. What is the mass of the bananas
Answer:
Mass of banana = 0.0657 kg
Step-by-step explanation:
We are given;
Amplitude; A = 0.15m
Spring constant;k = 16 N/m
Maximum velocity;v_max = 2.34 m/s
Now, In oscillatory motion, maximum velocity is given by;
V_max = Aω
Where A is amplitude and ω is angular velocity.
Making ω the subject, we have;
ω = V_max/A
ω = 2.34/0.15
ω = 15.6 rad/s
Now, For spring, angular velocity is given as;
ω = √(k/m)
Where k is force constant and m is mass.
Thus, plugging in the relevant values, we have;
15.6 = √(16/m)
15.6² = 16/m
m = 16/15.6²
m ≈ 0.0657 kg