Question

A certain kind of glass has nblue = 1.650 for blue light and nred = 1.610 for red light. If a beam of white light (containing all colors) is incident at an angle of 30.0º, what is the angle between the red and blue light inside the glass

Answer 1

angle between the red and blue = 1.26°

Step-by-step explanation:

given data

Refractive index For blue = 1.650

Refractive index For red = 1.610

Incident angle = 30°

solution

we will Use here Snell's law that is express as

`(sin(i))/(sin(r))` = n .................1

so we get here refraction angle for both blue and red

so for blue ray it will be put value in equation 1

`\frac{sin(i)}{\sin{r_(b)}} = n(blue)`

`\frac{sin(30)}{\sin{r_(b)}}` = 1.650

`sin({r_(b)})` = 0.3030

`{r_(b)}` = 17.64°

and

for red ray it will be put value in equation 1

`\frac{sin(30)}{\sin{r_(r)}}` = 1.610

`\sin({r_(r)} )` = 0.3105

`r_(r)` = 18.09°

so

angle between the red and blue will be as

angle between the red and blue =
`r_(r) - {r_(b)}` ................2

put here value

angle between the red and blue = 18.09° - 17.64°

angle between the red and blue = 1.26°