How many L of 0.75 M Ca(OH)2(aq) are needed in order to have 5.5 mol of Ca(OH)2?

asked Dec 26, 2021 47.2k views

3 votes

7.0k points

Please log in or register to add a comment.

6 votes

Answer:

7 1/3 L.

Step-by-step explanation:

1 liter of 0.75 M Ca(OH)2 aq contains 1 mole of Ca(OH)2.

By proportion that would be 5.50 / 0.75 L

= 7 1/3 L.

SnellyBigoda answered Dec 30, 2021

7.6k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

7.8m questions

10.5m answers