How many L of 0.75 M Ca(OH)2(aq) are needed in order to have 5.5 mol of Ca(OH)2?

asked Dec 26, 2021 47.2k views

3 votes

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6 votes

Answer:

7 1/3 L.

Step-by-step explanation:

1 liter of 0.75 M Ca(OH)2 aq contains 1 mole of Ca(OH)2.

By proportion that would be 5.50 / 0.75 L

= 7 1/3 L.

SnellyBigoda answered Dec 30, 2021

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