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If a ball is thrown upward at 29.4 meters per second from the top of a building that is 80 meters high, the height of the ball can be modeled by S=4.9t^2 + 29.4t + 80 meters, where t is the number of seconds after the ball is thrown. What is the ball's maximum height (in meters)?

User Vanhooser
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1 Answer

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Answer:

1.5 seconds

Explanation:

The vertex is (1.5, 82.05) which gives you your time value of 1.5 seconds, and the max height value of 82.05. So the max height is 82.05 m and it reaches that height at 1.5 seconds.

User Ayurchuk
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