Question

The final velocity is_________________________________ m/s for a hollow spherical ball with mass of 0.03 kg that rolls (without slipping) down a slope with height of 12m.

Answer 1

Step-by-step explanation:

Using conservation of energy

Change in potential energy is equal to change in kinetic energy

∆P.E = ∆K.E

The initial K.E is zero

The final potential energy is zero

mgh = ½mv²

m cancels out

gh = ½v²

v² = 2gh

v = √2gh

Given that h = 12m

g is constant = 9.81m/s²

v =√2×9.81×12

v = √235.44

v = 15.34 m/s

The final velocity is 15.34m/s