Question

8

A 0.200 L cup of tea contains 3.765 g sucrose, which has a molecular weight of 342.3
mol
42.3
What is the molar concentration of sucrose in the tea?
Express the answer using 3 significant figures.

Answer 1

.054

Step-by-step explanation:

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Answer 2

Answer : The molar concentration of sucrose in the tea is, 0.0549 M

Explanation : Given,

Mass of sucrose = 3.765 g

Volume of solution = 0.200 L

Molar mass of sucrose = 342.3 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

`\text{Molarity}=\frac{\text{Mass of sucrose}}{\text{Molar mass of sucrose}* \text{Volume of solution (in L)}}`

Now put all the given values in this formula, we get:

`\text{Molarity}=(3.765g)/(342.3g/mole* 0.200L)=0.0549mole/L=0.0549M`

Therefore, the molar concentration of sucrose in the tea is, 0.0549 M