Two cards are chosen at random without replacement from a pack of 52 playing cards. If the first card chosen is an Ace, what is the probability the second card chosen is a King?

My account
Edit my Profile
Private messages
My favorites

Ask a Question
Questions
Tags
Categories
Ask a Question

Yarco asked Dec 6, 2023

35,494 views

11 votes

Two cards are chosen at random without replacement from a pack of 52 playing cards. If the first card chosen is an Ace, what is the probability the second card chosen is a King?

Mathematics
college

Yarco asked Dec 6, 2023

by Yarco

2.5k points

0 Comments

Your comment on this question:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Your answer

Email me at this address if my answer is selected or commented on:Email me if my answer is selected or commented on

Privacy: Your email address will only be used for sending these notifications.

2 Answers

11 votes

Answer:

the probabilyy of that will probably be the probability of that question porbably speaking about probability

Mel answered Dec 8, 2023

by Mel

3.1k points

0 Comments

Your comment on this answer:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

7 votes

Answer:

4/52 or 1/13

Explanation:

HyperionX answered Dec 11, 2023

by HyperionX

3.5k points

0 Comments

Your comment on this answer:

Email me at this address if a comment is added after mine:Email me if a comment is added after mine

Privacy: Your email address will only be used for sending these notifications.

Ask a Question

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

1.6m questions

2.0m answers

0 Comments

Your comment on this question:

Your answer

2 Answers

0 Comments

Your comment on this answer:

0 Comments

Your comment on this answer:

Other Questions