Question

Question 2 (1 point)

1. What is the molarity of 5.30 g of calcium chloride dissolved in 0.5 L solution?
0.02 M
10.6 M
0.1 M
Od 2.65 M
Question 3 (1 point)

Answer 1

The molarity of the given solution is 0.1 M.

Step-by-step explanation:

We have to find the molarity of calcium chloride by converting the mass of CaCl₂ into its moles and dividing it by its volume in Litres.

We have to find the moles by dividing the mass of the substance by its molar mass.

Moles of CaCl₂ =
`$(mass)/(molar mass)`

=
`$(5.30 g )/(110.98 g/mol)`

= 0.05 moles

Molarity =
`$(moles)/(volume(L))`

=
`$(0.05 moles)/(0.5 L)`

= 0.1 M

So the molarity of the given solution is 0.1 M.