Question

Find the 6th term of the following geometric sequence:
2, 8, 32, 128, ...

Answer 1

Explanation:

t1 = 2= 2 * 4 ^ 1 -1

t2 = 8= 2* 4^2-1

t3 = 32= 2 * 4^3 -1

t4 = 128 = 2* 4^ 4 -1

----------------------------

tn = 2 * 4^ (n - 1)

Now

the 6th term of the sequence is

t6 = 2 * 4^ 6 -1

= 2 * 1024

= 2048

hope it was helpful.

Answer 2

Answer: 2048

Step-by-step explanation: u have to multiply each term by 4