Question

Juanita has 3 rectangular cards that are 8 inches by 9 inches. How can she arrange the cards, without overlapping, to make one larger polygon with the smallest possible perimeter? How will the area of the polygon compare to the combined area of the 3 cards?

Answer 1

Explanation:

Given

• 3 rectangular cards
• each card is 8 inches by 9 inches

The way that she can arrange the cards, without overlapping, to make one larger polygon with the smallest possible perimeter is that:

Put 3 cards together according to the length

So the smallest possible perimeter is:

8 + 8 + 8 + 8 + 8 + 8 + 9 + 9 = 66 inches as you can see in the attached photo.

The area of the polygon is equal to the combined area of the 3 cards without overlapping or extending.

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