Question

A helium balloon has an internal pressure of 1.05 atm and a volume of 5.0 L. If the temperature where the balloon is released is 20 °C, what will happen to the volume when the balloon rises to an altitude where the pressure is 0.65 atm and the temperature is –15 °C? *round to 2 decimal places

Answer 1

x = 7.11 L

Step-by-step explanation:

(1.05 atm)(5.0 L)/(293 K) = (0.65 atm)(x L)/(258 K)

use an algebraic expression to simplify