160k views
5 votes
What is the missing constant term in the perfect square that starts with

x2+14xx^2+14x
x
2
+14x
x, squared, plus, 14, x
?

User Deamon
by
6.3k points

2 Answers

3 votes

Answer:

49 khan

Explanation:

User JofoCodin
by
5.9k points
5 votes

Answer:

49

Explanation:

The expression is given below:

x^2 + 14x

Let y be the constant that will make the expression a perfect square. Therefore, the expression can be written as:

x^2 + 14x + y

Applying the formula b^2 = 4ac, we can easily obtain the value of y as shown below:

x^2 + 14x + y

Coefficient of x^2 (a) = 1

Coefficient of x (b) = 14

Constant (c) = y

b^2 = 4ac

14^2 = 4 x 1 x c

196 = 4c

Divide both side by the coefficient of c i.e 4

c = 196/4

c = 49

Thus, 49 must be added to the expression to make it a perfect square.

User Shagberg
by
6.9k points
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