5. What is the potential energy of a spring if the spring constant is 25.0 N/m and it is compressed to .5 m past its resting position?

asked Apr 8, 2023 53.1k views

12 votes

by JDawg

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6 votes

Step-by-step explanation:

Given: Required: solution:

k=25N/m PE ? PE= 1/2 × KX²

X= 5m 1/2 × (25)(5)²

= 312.5 J

Quyen answered Apr 14, 2023

by Quyen

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