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If 0.20 moles of helium occupies a volume of 64.0L at a pressure of 0.15atm, what is the temperature of the gas?

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Answer:0.20 moles of Helium gas that initially occupies a volume of 4.0L under a total pressure of 1.0x10^5 Pa, subsequently undergoes an isobaric expansion to 5.0L followed by an isothermal expansion to 8.0L.

a.) What is the total work done for the entire process?

b.) What is the internal-energy change of the gas for the entire process? Does the internal energy of the gas increase or decrease? Explain briefly.

c.) What is the total heat transferred for the entire process? Does the gas absorb heat from the surroundings or does it release heat to the surroundings? Explain briefly.

d.) Draw the entire process on the P-V diagram provided below. Label the region on the graph that represents the total work done.

For monoatomic gases like Helium, specific heat at constant volume Cv = 12.5 J/mol-K For monoatomic gases like Helium, specific heat at constant pressure Cp = 20.8 J/mol-K Using p1V1 = n

Explanation: don't worry abt it :)

If 0.20 moles of helium occupies a volume of 64.0L at a pressure of 0.15atm, what-example-1
User Ethan Heilman
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