Question

Find two numbers whose product is 3 and the sum of whose reciprocals is 76/15

Answer 1

xy=3_equation I

x+y=76/15 eq 2

Explanation:

from eq

x=3/y

now put x=3/y in eq 2

3/y+y=76/15

(3+y^2) 15=76y

45+15y^2=76y

15y^2-76y+45=0

by using quardic equation

x=76+_root under 76^2-4×15×45/2×15

y= 5776+- 53.62/2×15

taking positive sign and taking negative sign

y=194.32

y=190.745