Answer:
The sum of the first 6 terms of the series is 504.
Explanation:
Given that,
Common ratio in a geometric series is, r = 0.5
First term of the series, a = 256
We need to find the sum of the first 6 terms in the series. If a and r area the first term and common ratio of a series, then the series becomes:
![a,ar^1,ar^2,ar^3......](https://img.qammunity.org/2021/formulas/mathematics/high-school/7zgyqqbxyebatdkwkthdtvolb0hgx3n581.png)
The sum of n terms of a GP is given by :
![S_n=(a(1-r^n))/(1-r)](https://img.qammunity.org/2021/formulas/mathematics/high-school/j9yud756jc8a0pcpopyckm7cy0y3ip3qhc.png)
Here, n = 6
![S_n=(256* (1-(0.5)^6))/(1-0.5)\\\\S_n=504](https://img.qammunity.org/2021/formulas/mathematics/high-school/kacdw6phv91ot373d7vbz3i4q41l5as29k.png)
So, the sum of the first 6 terms of the series is 504.