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The length of a rectangle is 5yd longer than its width. If the perimeter of the rectangle is 70yd , what is its length and width.

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Final answer:

To solve this problem, set up equations using the given information. The width of the rectangle is 15 yards and the length is 20 yards.

Step-by-step explanation:

To solve this problem, we can set up equations using the given information. Let's say the width of the rectangle is x. According to the problem, the length of the rectangle is 5 yards longer than its width, so the length would be x+5.

The perimeter of a rectangle is calculated by adding up all four sides, which in this case would be 2(length) + 2(width). So the equation for the perimeter of the rectangle is: 2(x+5) + 2x = 70.

Simplifying the equation, we get 4x + 10 = 70. Subtracting 10 from both sides, we have 4x = 60. Dividing both sides by 4, we find that x = 15.

Therefore, the width of the rectangle is 15 yards and the length is x+5 = 20 yards.

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