Question

Sin x=0.6, x lies in quadrant two.

Answer 1

`\qquad\qquad\huge\underline{{\sf Answer}}`

Here we go ~

`\qquad \tt \dashrightarrow \: \sin(x) = 0.6`

`\qquad \tt \dashrightarrow \: \sin(x) = (6)/(10)`

`\qquad \tt \dashrightarrow \: \sin(x) = (3)/(5)`

`\qquad \tt \dashrightarrow \:x = \sin {}^( - 1) ( (3)/(5) )`

`\qquad \tt \dashrightarrow \:x = 37 \degree`

Now, since we have to find the value of x in quadrant 2, we have to subtract the given value from 180°

that is :

`\qquad \tt \dashrightarrow \:x = 180 - 37`

`\qquad \tt \dashrightarrow \:x = 143 \degree`