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How many liter are in 55.5 grams of neon?

User SnoProblem
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1 Answer

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MolesofAr(n)= given mass/ molar mass of neon= 55.5/20.17=2.75moles

Volume of the gas = 2.75moles x 22.4L=61.63L

The answer to the question is-61.63L
User Tony Morris
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