17.5k views
2 votes
For the factored form of the Quadratic equation -2(x+ 1) (x +13)

The zeros/Roots are

. The axis of Symmetry is

. The vertex is

. The y intercept is



1 Answer

5 votes

Answer:

Let's work through the information for the factored form of the quadratic equation -2(x + 1)(x + 13):

1. Zeros/Roots: The zeros or roots are the values of x that make the quadratic equation equal to zero. To find them, set the equation equal to zero and solve for x:

-2(x + 1)(x + 13) = 0

Set each factor equal to zero and solve for x:

x + 1 = 0 => x = -1

x + 13 = 0 => x = -13

So, the zeros/roots are x = -1 and x = -13.

2. Axis of Symmetry: The axis of symmetry for a quadratic equation in the form y = a(x - h)^2 + k is given by x = h. In the case of your equation, it's already in factored form, so you can determine the axis of symmetry by averaging the zeros:

Axis of symmetry = (-1 - 13) / 2 = -14 / 2 = -7

So, the axis of symmetry is x = -7.

3. Vertex: The vertex of the quadratic equation can be found using the axis of symmetry. Since the axis of symmetry is x = -7, plug this value into the equation to find the corresponding y-value:

-2(-7 + 1)(-7 + 13) = -2(-6)(6) = -72

So, the vertex is (-7, -72).

4. Y-Intercept: The y-intercept occurs when x = 0. Plug x = 0 into the equation:

-2(0 + 1)(0 + 13) = -2(1)(13) = -26

So, the y-intercept is at y = -26.

To summarize:

Zeros/Roots: x = -1 and x = -13.

Axis of Symmetry: x = -7.

Vertex: (-7, -72).

Y-Intercept: y = -26.

Explanation:

User AliR
by
4.8k points