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3 votes
What pressure does a 130-pound women exert on the floor when she

balances on one of her heels? Her heels have a radius of 0.25 inches. *

User Ricsrock
by
5.6k points

1 Answer

4 votes

Answer:

Pressure,
P=4.56* 10^6\ Pa

Explanation:

Given that,

Force exerted by woman on the floor, F = 130 pounds = 578.26 N

Radius of her heels, r = 0.25 inches = 0.00635 m

We need to find the pressure exerted by woman on the floor. We know that pressure exerted by an object is equal to the force acting per unit area. So,


P=(F)/(A)\\\\P=(578.26 \ N)/(\pi (0.00635\ m)^2)\\\\P=4.56* 10^6\ Pa

So, the pressure exerted by the woman on the floor is
4.56* 10^6\ Pa.

User Spoekes
by
4.7k points
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