Question

What is the change in boiling point for a 0.615m solution of Mgl2 in water?

Answer 1

Answer : The change in boiling point is,
`0.94^oC`

Explanation :

Formula used :

`\Delta T_b=i* K_f* m`

where,

`\Delta T_b` = change in boiling point = ?

i = Van't Hoff factor = 3 (for MgI₂ electrolyte)

`K_f` = boiling point constant for water =
`0.51^oC/m`

m = molality = 0.615 m

Now put all the given values in this formula, we get

`\Delta T_b=3* (0.51^oC/m)* 0.615m`

`\Delta T_b=0.94^oC`

Therefore, the change in boiling point is,
`0.94^oC`