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19 votes
19 votes
V
Find the angle between v=i+2j+3k and w=4i-k.
:2
.

User Monea
by
3.1k points

1 Answer

29 votes
29 votes

Answer:

86.28 degrees

Explanation:

Angle between vectors is


\cos(x) = (cross \: product)/(magnitudes \: multiplied)

The cross product is


4 + 0 - 3 = 1

The magnitudes of first vector is


\sqrt{1 {}^(2) + 2 {}^(2) + 3 {}^(2) } = √(14)

The second vector magnitude is


√(17)

So the magnitudes multiplied is


√(14) * √(17) = √(238)

So our equation will be


\cos(x) = (1)/( √(238) )


x = \cos {}^( - 1) ( (1)/( √(238) ) )

X is about 86.28 degrees

User Jeffkee
by
3.1k points
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