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How many moles of ammonium carbonate are needed to decompose in order to produce 6.52g of carbon dioxide? Ammonium oxide is the other product.

A.) 0.116 moles

B.) 0.251 moles

C.) 0.148 moles

D.) 286.88 moles


Help me solve please...

User Elwhis
by
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1 Answer

4 votes

Answer:

Option (C) is correct.

Step-by-step explanation:

Decomposition reaction:
(NH_(4))_(2)CO_(3)\rightarrow 2NH_(3)+CO_(2)+H_(2)O

Molar mass of
CO_(2) = 44.01 g/mol

No. of moles = (mass)/(molar mass)

So, 6.52 g of
CO_(2) =
(6.52)/(44.01) moles of
CO_(2) = 0.148 moles of
CO_(2)

According to balanced equation-

1 mol of
CO_(2) is produced from decomposition of 1 mol of
(NH_(4))_(2)CO_(3)

So, 0.148 mol of
CO_(2) is produced from decomposition of 0.148 mol of
(NH_(4))_(2)CO_(3)

Hence, option (C) is correct.

User Akshay G
by
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