Question

You want the current amplitude through a 0.450-mH inductor (part of the circuitry for a radio receiver) to be 1.90 mA when a sinusoidal voltage with an amplitude of 13.0 V is applied across the inductor.What frequency is required?

Answer 1

Frequency required will be 2421.127 kHz

Step-by-step explanation:

We have given inductance
`L=0.450H=0.45* 10^(-3)H`

Current in the inductor
`i=1.90mA=1.90* 10^(-3)A`

Voltage v = 13 volt

Inductive reactance of the circuit
`X_l=(v)/(i)`

`X_l=(13)/(1.9* 10^(-3))=6842.10ohm`

We know that

`X_l=\omega L=2\pi fL`

`2* 3.14* f* 0.45* 10^(-3)=6842.10`

f = 2421.127 kHz