Question

Jamie is picking two vegetables to put in her stir fry. She has 3 carrots, 2 cabbages, 4 leeks, and one mushroom to choose from.

If she only is going to pick two at random, what is the probability she picks a carrot then a leek?
03/25
O 2/15
0 3/10
O 7/10

Answer 1

To find the probability of Jamie picking a carrot and then a leek, multiply the individual probabilities of each event occurring in sequence. First, pick a carrot (3/10 chance) and then a leek (4/9 chance) resulting in a probability of 2/15.

Step-by-step explanation:

The question asks for the probability of Jamie picking a carrot and then a leek for her stir fry. Here are the steps to find the solution:

1. Count the total number of vegetables Jamie has, which is 3 carrots + 2 cabbages + 4 leeks + 1 mushroom = 10 vegetables.
2. Calculate the probability of picking one carrot out of the 10 vegetables, which is 3/10.
3. Since one vegetable has been removed after picking a carrot, there are now 9 vegetables left. Calculate the probability of picking a leek now, which is 4/9.
4. To find the total probability of both events occurring, multiply the probabilities together: (3/10) * (4/9).

Therefore, the probability of picking a carrot then a leek is 2/15 when simplified.

Answer 2

B) 2/15

Step-by-step explanation:

In total, she has 10 choices, after she chooses one, she has 9 choices.

The probability to choose a carrot is 3/10, and then a leeks is 4/9.

Multiply them together to get

3/10 * 4/9 = 12/90

Simplify

2/15