Answer:
8 nickels
Explanation:
Total Amount of Money owned by Jason=$10
1 nickel =$0.05
1 dime=$0.10
1 quarter =$0.25
- Let the number of dimes =d
- Let the number of nickels =n
- Let the number of quarters =q
If there were twice as many dimes as Nickels, then:
Also, there were twice as many quarters as dimes.
Therefore:
0.1d+0.05n+0.25q=100
Substituting d=2n and q=2d into the above relations
0.1(2n)+0.05n+0.25(2d)=10
0.2n+0.05n+0.25(2(2n))=10
0.2n+0.05n+1n=10
1.25n=10
n=8
q=2d=2X16=32
d=2n=2X8=16
Jason had 8 nickels