Question

Which quadratic equation defines the function that has zeros at -8 and 6?

A. x^2 + 2x - 48 = 0
B. x^2 - 2x - 48 = 0
C. x^2 + 2x + 48 = 0
D. x^2 - 2x + 48 = 0

Answer 1

Answer: it is A

Explanation:

x^2+2x-48=0

x^2+8x-6x-48=0

x×(x+8)-6(x+8)=0

(x+8)×(x-6)=0

x+8=0

x-6=0

x=-8

x=6