Question

What is the y-intercept of the graph of p(x)=-3(x-2)²+4

Answer 1

(0,-8)

Explanation:

The y intercept occurs when x = 0 , so put in x = 0

-3(0-2)^2 + 4 = -8

so y-axis intercept is ( 0, -8 )

Answer 2

The y intercept is -8, or (0, -8)

Explanation:

p(x)=-3(x-2)²+4

p(x)=-3(x²-4x+4)+4

p(x)=-3x²+12x-12+4

p(x)=-3x²+12x-8

This is quadratic

In p(x)=ax²+bx+c

c is the y intercept

Therefore the y intercept is -8, or (0, -8)

Hope this helps! :D

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