Answer:
a) 5180
Explanation:
We must calculate with respect to each of the options:
a) 5180
We have that the mean (m) is equal to 5850, the standard deviation (sd) 1125 and the sample size (n) = 20
They ask us for P (x <5180)
For this, the first thing is to calculate z, which is given by the following equation:
z = (x - m) / (sd / (n ^ 1/2))
We have all these values, replacing we have:
z = (5180 - 5850) / (1125 / (20 ^ 1/2))
z = -2.66
With the normal distribution table (attached), we have that at that value, the probability is:
P (z <-2.66) = 0.0039
Which means that the probability is 0.39%, which is a very low probability, which is not necessary to calculate the other options, we already know that this data is very unusual.