3.84 Kg of sodium chloride is needed to lower the freezing point of the water so that ice melts.
Step-by-step explanation:
Data given:
mass of ice = 30 Kg
molar mass of NaCl = 58.5 grams/mole
ΔT(depression in freezing point) = 15.4 F or - 9.22 degrees
Kf = 1.86 degree C/ mole
Molality = ?
mass of NaCl =?
i = 2 (because NaCl breaks into 2 ions)
ΔT = iKfm equation 1
Depression in freezing point when ice melts, the temperature is 0 degrees so
the depression in temperature = 9.22 degrees
putting the values in the equation:
9.22 = 2 x 1.86 x
x

mass = 3.84 kg of NaCl will be required to lower the freezing point of the water so that the ice melts.