Answer:
(A) $7,294.595 approximately $7,295
(B) In this case we are dealing with competition for refurbished cars across cities, not avoidance of cash loss hence the answer is the function:
(PC1 + PC2 + PC3 + ... + PCn) ÷ n
(C) The smallest average price is $7,200
Step-by-step explanation:
(A) The smallest average price that the company can afford to charge for refurbishing 1 car is the price at which Total Revenue equals Total Cost
TR = TC
TR = price × quantity
TC = TFC + TVC
TR = 37P
TC = $3,500 + (VC × Q)
where total variable cost is equal to variable cost multiplied by the quantity of cars
TC = $3,500 + ($7,200 × 37)
TC = $3,500 + $266,400 = $269,900
Equating Total Revenue to Total Cost,
37P = $269,900
P = $7,294.595 approximately $7,295
(B) Since the specific prices at which the cara are sold across the various cities are not given, our solution will be a function which is equal to the average of the prices across cities.
(PC1 + PC2 + PC3 +...+ PCn) ÷ n
where n = the number of cities where the company's refurbished cars are sold
PC1 = the price at which the cars are sold in the first city or in City labelled "1"
And so on and so forth
(C) In this case, total cost is equal to total variable cost since no new fixed cost is incurred (since no new assets or infrastructure are required or acquired).
Once again, the smallest average price the company can or should charge is the price at which total revenue equals total cost.
Here,
TR = PR
Where P is the price we are looking for and R is the quantity/volume of cars in the new year.
TC = TVC = $7,200R
Equating TR to TC, we have
PR = $7,200R
Divide both sides by R to get the desired variable P
P = $7,200