Answer:
The answer is 1,275,120
Explanation:
The goal of this is to determine the number of strings of strings of six lowercase letters from the English alphabet that contain the letters a and b in positions consecutive with a preceding b, with all the letters distinct.
Now,
As the letters a and b are consecutive, the possible string outcomes are in this form:
ab_ _ _ _
_ab_ _ _
_ _ab_ _
_ _ _ ab_
_ _ _ _ ab
As seen here, ab can denoted in five locations as in C (5, 1) = 5 ways
we use the permutation for the order of the letters to be needed.
so,
n= 24, r =4
p (24, 4) = 24ǃ /( 24 - 4)ǃ
= 24ǃ /20ǃ
=255,024
Now, the number of possible strings is 5* 255.024 = 1,275,120.
In conclusion there are 1,275,120 number of strings of six lowercase letters from the English alphabet contain the letters a and b in consecutive positions with a preceding b, with all the letters distinct.