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Credit card balances follow a nearly normal distribution with a mean of $2,900 and a standard deviation of $860. A local credit union believes their customers are carrying an above average credit card balance, so they carry out a study to determine their customers' debt. If the study results in a standard error of $43, what sample size was used in the study

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Answer:

A sample size of 400 was used in the study.

Explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean
\mu and standard deviation
\sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
\mu and standard deviation(standard error)
s = (\sigma)/(√(n)).

In this problem, we have that:


\sigma = 860, s = 43

We have to find n.


s = (\sigma)/(√(n))


43 = (860)/(√(n))


43√(n) = 860


√(n) = (860)/(43)


√(n) = 20


(√(n))^(2) = 20^(2)


n = 400

A sample size of 400 was used in the study.

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