Question

If you were to separate all of the electrons and protons in 1.00 g (0.001 kg) of matter, you’d have about 96,000 C of positive charge and the same amount of negative charge. If you placed these charges 8.00 m apart, how strong would the attractive forces between them be?

Answer 1

The attractive force between them is
`1.296 * 10^(18)` N

Step-by-step explanation:

Given:

Charge
`q = 96000` C

Distance between two charges
`r = 8` m

According to the coulomb's law,

`F = (kq^(2) )/(r^(2) )`

Where
`k = 9 * 10^(9)` = force constant.

`F = (9 * 10^(9) * (96000)^(2) )/(8^(2) )`

`F = 1.296 * 10^(18)` N

Therefore, the attractive force between them is
`1.296 * 10^(18)` N