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A solution is prepared by dissolving 0.23 mol of acetic acid and 0.27 mol of sodium acetate in water sufficient to yield 1.00 L of solution. The addition of 0.05 mol of HCl to this buffer solution causes the pH to drop slightly. The pH does not decrease drastically because the HCl reacts with the __________ present in the buffer solution.

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Answer:

Acetate ion

Step-by-step explanation:

CH₃COOH ↔ CH₃COO⁻ + H⁺

HCl -> H⁺ + Cl⁻

The H+ ions from added HCl reacts with acetate ions and more amount of acetic acid will be formed due to common ion effect.

User Luc Gendrot
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