Answer:
27.60 g urea
Step-by-step explanation:
The freezing-point depression is expressed by the formula:
In this case,
- ΔT = 5.6 - (-0.9) = 6.5 °C
m is the molality of the urea solution in X (mol urea/kg of X)
First we calculate the molality:
- 6.5 °C = 7.78 °C kg·mol⁻¹ * m
Now we calculate the moles of urea that were dissolved:
550 g X ⇒ 550 / 1000 = 0.550 kg X
- 0.84 m = mol Urea / 0.550 kg X
Finally we calculate the mass of urea, using its molecular weight:
- 0.46 mol * 60.06 g/mol = 27.60 g urea