Answer:
the magnitude of the torque about the point where the beam is bolted into place 12.32kNm
Step-by-step explanation:
N/B The units given in the question are meant to be m, kg and kg respectively
Given data
Length of beam 3.7m
Mass of beam 520kg
Mass of construction worker 73kg
Torque is expressed as the moment or turning effect brought about by a couple
T= F*d
Where d=perpendicular distance
F= force
Converting The mass of the beam and the worker to force we have
520*10= 5200N
73*10=730N
Note that the force due to the mass of the beam is acting at the center of the beam
See the free body diagram attached
Taking moments about point O
Torque =Σ Fxd
Torque =5200x1.85+7x3.7
=9620+2701
=12321 Nm
=12.32kNm