Answer:
a)=0.6826
b)=0.6331
c))=0.1662
d)0.0016
Explanation:
Binomial Distribution refers to the distribution in whereby only two possible outcomes. It takes place whether the event is happening or not happening , irrespective of the number of trials.
Given:
p = 0.6, q = 1 - p = 0.4
a)P(At least 3 out of 5 days) = P(3) + P(4) + P(5)
P(X≥3)=P(X=3)+P(X=4)+P(X=5)=5C3×0.63×0.45−3+5C4×0.64×0.45−4+5C5×0.65×0.45−5
10×0.63×0.45- 3+5×0.64×0.45 - 4+1×0.65×0.45 - 5
=0.6826
(b)P(At least 6 out of 10 days)
p(X = 6) + p(X = 7) + p(X = 8) + p(X = 9) + p(X = 10) =
0.2508 + 0.2150 + 0.1209 + 0.0403 + 0.0061 = 0.6331
(c)P(5 out of 10 days )
checking the binomial distribution table
p(X < 5) =
p(X = 0) + p(X = 1) + p(X = 2) + p(X = 3) + p(X = 4) =
0.0001 + 0.0016 + 0.0106 + 0.0425 + 0.1114 =0.1663
(d)
P(X<6)=0.0016
P(X<6)=0.0016
from answer from option D, it shows that there is 0.16% chance distribution from the 20 random sample,then it can be concluded that P<0.60