Question

what is the molarity of a solution of hcl if 250 ml of a 0.50 m solution of naoh will completely neutralize 100.ml of this acid

Answer 1

The molarity of the acid is 1.25 M.

Step-by-step explanation:

We have to find the molarity of HCl by writing the balanced equation that is the neutralization reaction of Hydrochloric acid with the base, Sodium Hydroxide, NaOH.

HCl + NaOH → NaCl + H₂O

From the balanced equation, we can find that one mole of an acid is used to neutralize one mole of a base.

As per the law of volumetric analysis, we can write the equation as,

V1M1 = V2M2

Here V1 and M1 being the volume and molarity of the NaOH

V2 and M2 being the volume and molarity of HCl

V1 = 250 ml

M1 = 0.50 M

V2 = 100 ml

M2 = ?

Now the above equation can be rearranged to find the molarity of the acid as,

M2 =
`$(V1M1)/(V2)`

=
`$(250 ml * 0.50 M)/(100 ml)`

= 1.25 M

So the molarity of the acid is 1.25 M.