Question

Help pretty please!

Cyrus lives 11 miles due south of Adriana, Adriana live 19 miles due west of Jane, Jane lives 12 miles due south of Madisyn.

The shortest distance between Cyrus' house and Jane's house is

•21.95
•481.802
•0.52

The shortest distance between Adriana's house and Madisyn's house is

•504.901
•22.47
•44.42

Answer 1

A.) 21.95

B.)22.47

Explanation:

A.) An easy way to solve this is to use the Pythagorean theorem. Since the only person between Cyrus and Jane is Adriana, we will use her as a measuring point. Adriana's distance to Jane is 19, we will set a = 19, Adriana also is 11 miles away from Cyrus, and we will set b = 11. Now we plug it into the Pythagorean theorem.

`a^2+b^2=c^2\\19^2+11^2=c^2\\√(482) =√(c^2)\\ 21.95=c`

B.) Using the same principle but for Adriana and Madisyn, we will use Jane as she is between them. Adriana is 19 miles from Jane, so we will set a=19, Madisyn is also 12 miles from Jane, so we will set b=12. Plug it for the Pythagorean theorem.

`a^2+b^2=c^2\\19^2+12^2=c^2\\505=c^2\\√(505)=√(c^2)\\ 22.47 = c`