The answer for the following problems is mentioned below.
- Therefore the number of moles present in Argon is 0.20 moles.
Step-by-step explanation:
Mole:
The mass of a substance containing the same number of fundamental units as there are atoms in exactly 12.000 g of
.
Given:
volume (v) = 4.7 litres
Volume of argon at STP conditions = 22.4 litres
To find:
volume of argon at STP conditions
We know;
n =
![(v)/(V)](https://img.qammunity.org/2021/formulas/chemistry/high-school/4s9lzlg6jen3clzfvsp0zh7ltuyi2xn8ba.png)
where;
n represents the no of moles
v represents the volume of the argon
V represents the volume of argon at STP
volume of the argon at STP conditions is 22.4 litres
So;
n =
![(4.7)/(22.4)](https://img.qammunity.org/2021/formulas/chemistry/high-school/xqeoxgeauyw3fh7j25lb1v1vipk4naenym.png)
n = 0.20 moles
Therefore the number of moles present in Argon is 0.20 moles.