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2 votes
Two number cubes are rolled.

What is the probability that the first lands on 2 and the second lands on a number greater than 4?




Enter you answer, as a fraction in simplified form, in the box.

User Luten
by
8.4k points

2 Answers

6 votes

Answer:

1/18

Explanation:

P(2) = 1/6

Greater than 4: 5,6

P(>4) = 2/6 = 1/3

1/6 × 1/3 = 1/18

User Safeta
by
7.8k points
2 votes

Answer:

1/18

Explanation:

Assuming the die are regular 1,2,3,4,5,6

P(2) = number of 2's/ total numbers on die

= 1/6

Roll again

Assuming the die are regular 1,2,3,4,5,6

P (numbers greater than 4) = {5,6}/total numbers on die

=2/6 = 1/3

P (2, then number greater than 4) = 1/6 * 1/3 = 1/18

User Ertugrul
by
9.3k points

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