Question

Write the first six terms of the sequence.

with an explanation please! i have no idea how to solve this on my own

Answer 1

49,36,25,16,9,4

Step-by-step explanation:

First, eliminate anwser A since it's all negatives, and when squaring, negatives (without imaginary numbers) are impossible.

Foil out the equation:

a=(n-8)^2

a=(n-8)(n-8)

a=n^2-8n-8n+64

a=n^2-16n+64

Now find the values by substituting values n>=1:

49=1^2-16(1)+64

36=4-32+64

etc.

Answer 2

Answer: Choice C)

49, 36, 25, 16, 9, 4

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Step-by-step explanation:

We always start with n = 1 when it comes to sequences and series problems.

Plug in n = 1 to get

`a_n = (n-8)^2\\\\a_1 = (1-8)^2\\\\a_1 = (-7)^2\\\\a_1 = 49\\\\`

The first term is 49, showing that the answer is choice C.

We can stop here, but I'll show how to do another one to help you get practice. Plug in n = 2.

`a_n = (n-8)^2\\\\a_2 = (2-8)^2\\\\a_2 = (-6)^2\\\\a_2 = 36\\\\`

I'll let you compute the other terms.