Question

PLEASE HELP THIS IS HARD

An experiment involves rolling two dice simultaneously. The following table shows the possible outcomes using the format of (die 1,die 2).

1 2 3 4 5 6
1 (1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
2 (2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
3 (3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
4 (4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
5 (5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
6 (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

What is the probability of rolling two numbers with a sum that is less than 7?

Enter your answer as a reduced fraction, like this: 3/14

Answer 1

5/12

Explanation:

1 (1,1) (1,2) (1,3) (1,4) (1,5) -5

2 (2,1) (2,2) (2,3) (2,4) -4

3 (3,1) (3,2) (3,3) -3

4 (4,1) (4,2) -2

5 (5,1) - 1

I took each row from the table and deleted the die rolls that added up to less than 7.

(In row 1 there were 5 rolls, in row 2 there were 4 rolls, and so on)

Then add the number of rolls. (5+4+3+2+1= 15)

Find the total number of possible rolls [(6)(6)=36]

Put them in fraction form, rolls that are less than 7/total number of rolls

You get 15/36

Reduce the fraction by adding the numerator and the denominator by 3.

Your final answer is 5/12.