How much concentrated 5.24M sulfuric acid is need to prepare 4.4 mL of a 5.29M solution

asked Apr 12, 2021 63.5k views

1 vote

8.2k points

Please log in or register to add a comment.

3 votes

Answer:

V1= 4.44ml

Step-by-step explanation:

C1= 5.24M V2=?, C2= 5.29, V2= 4.4ml

Applying dilution formula

C1V1=C2V2

5.24×V1 = 5.29×4.4

V1 =4.44ml

Sharp Johnny answered Apr 16, 2021

7.9k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers