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Given f(x) = x² - 10x + 22, what is the range of f?

User Bradjcox
by
4.6k points

2 Answers

4 votes

Answer:

The correct answer is B

Explanation:

User Instinct
by
5.5k points
3 votes

Answer:

[-3, ∞)

Explanation:

There are many ways to find the range but I will use the method I find the easiest.

First, find the derivative of the function.

f(x) = x² - 10x + 22

f'(x) = 2x - 10

Once you find the derivative, set the derivative equal to 0.

2x - 10 = 0

Solve for x.

2x = 10

x = 5

Great, you have the x value but we need the y value. To find it, plug the x value of 5 back into the original equation.

f(x) = x² - 10x + 22

f(5) = 5² - 10(5) + 22

= 25 - 50 +22

= -3

Since the function is that of a parabola, the value of x is the vertex and the y values continue going up to ∞.

This means the range is : [-3, ∞)

Another easy way is just graphing the function and then looking at the range. (I attached a graph of the function below).

Hope this helped!

Given f(x) = x² - 10x + 22, what is the range of f?-example-1
User IlBarra
by
4.7k points