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How do i solve this? - Linear Functions

How do i solve this? - Linear Functions-example-1
User Stubotnik
by
6.3k points

1 Answer

6 votes

Answer:

solve for y

Explanation:


5x-2y=-10

subtract 5x from both sides


5x-5x-2y=-10-5x


-2y=-10-5x

Divide each term in the equation by -2


(-2y)/(-2)=(-10)/(-2) -(-5x)/(-2)\\\\y=(-10)/(-2) +(-5x)/(-2) \\\\y=5+(5x)/(2)

(negative+negative=positive)

re-write in slope-intercept form
y=mx+b , where m is the slope and b is the y-intercept


y=(5)/(2)x+5

Now you know that the slope is
(5)/(2)x and the y-intercept is
5.

Now, to graph, you just need to choose random values for x (like 0,1,2,3 or any other number) and insert into the equation
y=(5)/(2)x+5 to find the points, or you can just use the slope. To find the x-intercept, do the following:

make y equal to 0


0=(5)/(2)x+5

Solve for x:

simplify
(5)/(2)x


0=(5x)/(2) +5

Subtract 5 from both sides


0-5=(5x)/(2)+5-5\\ \\-5=(5x)/(2)

Multiply both sides by 2


2(-5)=2((5x)/(2))\\\\-10=5x

Divide both sides by 5


(-10)/(5)= (5x)/(5)\\\\-2=x

Flip


x=-2

The x-intercept is -2.

User Ben Darnell
by
7.3k points
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