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What is the are of a rectangle with the height of 2x^4 and a width of x^2+8x+15?

User Oscarz
by
3.1k points

2 Answers

5 votes

Answer:

2x^6 + 16x^5 + 30x^4

Explanation:

You just need to multiply the two together; it's the same as any rectangle.

What is the are of a rectangle with the height of 2x^4 and a width of x^2+8x+15?-example-1
User Baczek
by
3.5k points
5 votes

Answer:

the length is x+5

Explanation:

1.(x^2+8x+15)/(x+3)

2.(x+5)(x+3)(x+3)X=5

User Sean Lynch
by
3.1k points