119k views
0 votes
What average force is required to stop a 1400 kg car in 8.0 s if the car is traveling at 95 km/h?

User HerbertD
by
5.1k points

1 Answer

3 votes

Answer: -424.24 N

It's negative because the vehicle is in motion and we want to bring it to a full stop, therefore we must apply a force in the opposite direction.

Step-by-step explanation:


F = ma\\\\F = Force\\m = mass (kg)\\a = acceleration (m/s^2)

Find the acceleration


V_1 = 95km/h\\V_2 = 0

Convert from km/h to m/s


95(km)/(h) ((1000m)/(1km) )((1h)/(3600s) )= 26.39m/s


a = (V_2-V_1)/(t)\\\\a = (0-26.39m/s )/(8s)\\\\a = -3.30m/s^2

Plug this information into the original Force Formula


F =ma\\\\F = (1400kg)(-3.30m/s^2)\\F =-424.24 N

User Sophocles
by
5.5k points